Solve the following pairs of equation by the substitution method
3x+4y=25
5x-6y=-9
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Answered by
0
(3x+4y=25) ====> 15x+20y=125 —(1)
(5x+4y=25) ====> 15x+12y=75 —(2)
Now :
(1)-(2)
(15x-15x) + (20y-12y) = 125-75
0+8y = 50
y = 25/4
3x+4y=25
3x + 4(25/4) = 25
3x = 0
x = 0
-----------------------------------------
(5x+4y=25) ====> 15x+12y=75 —(2)
Now :
(1)-(2)
(15x-15x) + (20y-12y) = 125-75
0+8y = 50
y = 25/4
3x+4y=25
3x + 4(25/4) = 25
3x = 0
x = 0
-----------------------------------------
Answered by
2
15x+20y=125----1
15x-18y=-27----2
2-1
-38y=-152
y=4
substitution
3x+4*4=25
3x=25-16
3x=9
x=3
15x-18y=-27----2
2-1
-38y=-152
y=4
substitution
3x+4*4=25
3x=25-16
3x=9
x=3
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