Question

solve the following pairs of equations graphically 3x-2y+8=0,2x+3y-12=​

Answer 1

Answer:

$3x - 2y + 8 = 0 - - (1),2x + 3y - 12 = 0 \\ x = \frac{2y - 8}{3} - - (2),2x + 3y = 12 - - (3) \\ using \: substitution \: method \\ using(2)into(3) \\ 2 (\frac{2y - 8}{3} ) + 3y = 12 \\ \frac{4y - 16}{3} + 3y = 12 \\ \frac{4y - 16 + 9y}{3} = 12 \\ 13y - 16 = 36 \\ 13y = 36 + 16 \\ 13y = 52 \\ y = \frac{52}{13} \\ y = 4 \\ using \: eq .\: y = 4in(3) \\ 2x + 3(4) = 12 \\ 2x+ 12 = 12 \\ 2x = 12 - 12 \\ x = \frac{0}{3} \\ x = 0$