solve the following pairs of linear equations 2x+3y=11 2x-4y=-24
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2x+3y=11...........(1)
2x-4y=-24..........(2)
by elimination method (1) from(2)
2x-4y = -24
2x+3y = 11
(-) (-) (-)
-----------------
-7y = -35( '-' cancel )
=7y = 35
= y = 35/7=5
y = 5.........(3)
put 3 in 1
= 2x + 3(5) = 11
= 2x + 15 =11
= 2x = 11 - 15
= 2x = -4
= x = -4/2= -2
= y = 5 ; x = -2
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2x-4y=-24..........(2)
by elimination method (1) from(2)
2x-4y = -24
2x+3y = 11
(-) (-) (-)
-----------------
-7y = -35( '-' cancel )
=7y = 35
= y = 35/7=5
y = 5.........(3)
put 3 in 1
= 2x + 3(5) = 11
= 2x + 15 =11
= 2x = 11 - 15
= 2x = -4
= x = -4/2= -2
= y = 5 ; x = -2
HOPE THIS HELPS YOU
PLEASE MARK ME AS BRAINLIEST
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