Question

Solve the following polynomial equation for x:x^2-2(a+2)x+(a+1)(a+3)=0

Answer 1

$hello \: \: friend \: \: \\ \\ this \: \: question \: \: can \: \: be \: \: solved \\ by \: \: two \: \: methods \: \:$
$(1) \: \: by \: \: middle \: \: term \: \: \\ splitting \: \: method$
$for \: \: this \: \: we \: \: expand \: \: the \: \: \\ middle \: \: term \\ according \: \: to \: \: the \: \: \\ question \:$
$a s\: \: our \: \: question \: \: is \: \: \\ {a}^{2} - 2 (a + 2 )x + ( a + 1 ) \: \\ \: (a + 2)$

SPLIT THE MIDDLE TERM AS
x^2 -(a+3) x - (a+1) x + (a+1)(a+3)


taking common


then
x{ a -(a+3)} -(a+1) { x-(a+3)}

{ x-(a+3)}{ x- (a+1)}


I hope this may help you

Answer 2

Answer:

The other person's answer is absolutely correct.Do thank him/her :)

Step-by-step explanation: