Solve the following problem::
Nisha scored 73,86,78 and 75 marks in four tests. What is the least number of marks she can score in her next test, if she has to have a mean score of 80 marks in five tests? !!
Answers
Answered by
2
★Hey there★
Let's say the sum of her scores in her first 4 exams are:----
73+86+78+75=312
Now she scores x in her fifth exam, so average
=Sum of events/Number of events
=312+x/5
Since Average=80, so
80=312+x/5
312+x=400
Therefore, she must score x=88 marks in her 5th test...
★HOPE IT HELPS★
Let's say the sum of her scores in her first 4 exams are:----
73+86+78+75=312
Now she scores x in her fifth exam, so average
=Sum of events/Number of events
=312+x/5
Since Average=80, so
80=312+x/5
312+x=400
Therefore, she must score x=88 marks in her 5th test...
★HOPE IT HELPS★
Answered by
3
Let Nisha scores x marks n her 5th test so as to have as mean score of 80 marks in her five test
A/Q
(73+86+78+75+x)/5=80
(312 + x)/5=80
312 + x=400
x= 88
So, Nisha has to score 88 marks in her 5th test so has to have a mean score of 80 marks in five test. Ans
A/Q
(73+86+78+75+x)/5=80
(312 + x)/5=80
312 + x=400
x= 88
So, Nisha has to score 88 marks in her 5th test so has to have a mean score of 80 marks in five test. Ans
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