Math, asked by prabhlynk, 10 months ago

Solve the following problem using LCM
(a) Find the least number which after being increased by 5 is exactly divisible by 7,12 and 14.

Answers

Answered by write2quantum

2

LCM Of 7, 12 , 14 is 84

Required number =84-5=79

When 79 is increased by 5 it becomes 84 which is divisible by 7,12,14.

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