Solve the following product of the following (2a+2b+3c)²
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Step-by-step explanation:
→ (a+b+c)² = a²+b²+c²-2ab-2bc-2ca
→ (2a)² + (2b)² + (3c)² - 2(2a)(2b) - 2(2b)(3c) - 2(3c)(2a)
→ 4a² + 4b² + 9c² - 8ab - 12bc - 12ca
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