Question

Solve the following Quadratic equation: √3x^2 - 2x - 8√3 = 0​

Answer 1

Answer:

Given:       √3x^2 - 2x - 8√3 = 0​

now,

      by splitting the middle term

⇒          √3x^2 - 6x + 4x - 8√3 = 0​

⇒       √3x ( x - 2√3) + 4 ( x - 2√3) = 0

⇒          (√3x + 4)( x - 2√3) = 0

now,

Case 1,

     √3x + 4 = 0

⇒       √3x = -4

∴         x = - 4/√3

Case 2,

        x - 2√3 = 0

∴          x = 2√3

∴ So there are two values of x = 2√3 and -4/√3

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