solve the following quadratic equation by factorisation 10 x minus one by x is equal to 3
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Answered by
37
10x-1/x=3 10x^2-1=3x
10x^2-3x-1=0
10^x-5x+2x-1=0
5x(2x-1)+1(2x-1)=0
(5x+1) (2x-1) =0
x=1/2 , -1/5
Answered by
9
Answer:
10x^2 -1/x = 3
= 10x^2 - 3x -1 =0
= 10x^2 - (5-2)x - 1 =0
= 5x(2x - 1) + 1 ( 2x - 1)=0
= (2x - 1) ( 5x + 1)= 0
either ,
2x- 1=0
or, x= 1/2.
or , 5x+1=0
or, x = - 1/5.
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