Question

solve the following quadratic equation by factorisation method. 3y squre — y — 10 = 0

Answer 1

3y^2 - y -10 =0
As 3✖️-10= -30 means we will find two numbers when we add or subtract them they will result-1y and by multiplication it’s will result -30y^2.
So
3y^2 -6y ➕ 5y -10 =0
Taking 3y as common from first two terms and 5 from last two terms
3y (y-2) ➕ 5(y-2) =0
(3y➕5) (y-2) =0
Either 3y➕5 =0
3y = -5
y =-5/3
Or y-2 =0
y=2
Solution set = {-5/3 , 2}

Answer 2

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