Question

Solve the following quadratic equation by factorisation method

Answer 1

Answer:

(y + 13)(2y + 1)

Step-by-step explanation:

27y can be split into y + 26y

→ 2y² + y + 26y + 13 = 0

→ y(2y+ 1) + 13(2y + 1) = 0

Therefore,

(y + 13)(2y + 1) = 0

Answer 2

Answer:

Zeroes are - 1/2 and - 13

Step-by-step explanation:

2y^2 +27y + 13 =0

2y^2 +26y + y +13

2y(y+13) +1(y+13)

(2y+1) (y +13)

Y = -1/2 and - 13