Solve the following quadratic equation by factorisation:x'2+10x+7=0
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Answered by
4
Answer:
x'2+10x+7=0
x'2+10x+25-18=0
(x+5)'2- 18=0
(x+5)'2-(√18)'2=0
(x+5-√18)(x+5+√18)=0
x+5-√18=0. ,. x+5+√18=0
x=√18-5. ,. x= -√18-5
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Answer:
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