Question

Solve the following quadratic equation by factorisation:x'2+10x+7=0​

Answer 1

Answer:

x'2+10x+7=0

x'2+10x+25-18=0

(x+5)'2- 18=0

(x+5)'2-(√18)'2=0

(x+5-√18)(x+5+√18)=0

x+5-√18=0. ,. x+5+√18=0

x=√18-5. ,. x= -√18-5

Answer 2

Answer:

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