When sanjay interchange the digits of a two digit number which is lesser than the original number by 36 , if the sum of the two digits of the number is 10 then what is the original number
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Let the tens digit be X and ones digit be y
Then, original no.= 10x + y
Interchanged no.= 10y + x
A.T.Q
10x + y= 10y + x +36
x-y = 4
Also,
x+y =10
Solve both the equation by elimination
you will get,
x=7
y=3
Hence, the original no. is 73
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