solve the following quadratic equation by factorisation: (x-7) (x-19)=64
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aloha user ✋☺️
( x - 7 ) ( x - 19 ) = 64
x( x - 19 ) -7( x - 19 ) = 64
x^2 - 19x -7x + 133 = 64
x^2 + 26x + 133- 64 = 0
x^2 + 26x + 69 = 0
x^2 + 3x + 23x + 69 = 0
x( x + 3 ) + 23 ( x + 3 ) = 0
( x + 23 ) ( x + 3) = 0
x = -23
x = -3
the required zeroes are -23 and -3.
good life !!
( x - 7 ) ( x - 19 ) = 64
x( x - 19 ) -7( x - 19 ) = 64
x^2 - 19x -7x + 133 = 64
x^2 + 26x + 133- 64 = 0
x^2 + 26x + 69 = 0
x^2 + 3x + 23x + 69 = 0
x( x + 3 ) + 23 ( x + 3 ) = 0
( x + 23 ) ( x + 3) = 0
x = -23
x = -3
the required zeroes are -23 and -3.
good life !!
SamratRoy:
Thank you
wlcm ☺️
my pleasure
How u got +26. ....... -19x-7x= -26x
oh sorry edit- that's +26... the zeroes will be positive then.
yes..
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