Math, asked by modiijain, 1 year ago

solve the following quadratic equation by factorisation x2+x-20=0​

Answers

Answered by guptarashi0790p9lgj0
20

Step-by-step explanation:

x²+x-20=0

x² + 5x - 4x - 20 =0

x( x + 5 ) -4 (x+5) =0

(x+5)(x-4) =0

x=-5 , x=4

Answered by ankitrawat1974
4

Answer:

x2+x-20=0

Step-by-step explanation:

then 20 is the factor of 5X4 = 20 and 5-4 =1 that is x then ur equation willl be

x2+5x-4x-20

x(x+5)-4(x+5)

(x+5) (x-4) = 0

x+5=o   x-4=0

x= -5     x=4

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