Question

solve the following quadratic equation by factorization method x^2+2√2x-6=0 ​

Answer 1

SOLUTION

$= > p(x) = {x}^{2} + 2 \sqrt{2} - 6 \\ = > {x}^{2} + 3 \sqrt{2x} - \sqrt{2} x - 6 = 0\\ = > x(x + 3 \sqrt{2}) - \sqrt{2} (x + 3 \sqrt{2} ) = 0 \\ = > (x - \sqrt{2} )(x + 3 \sqrt{2} ) = 0 \\ = > (x - \sqrt{2} ) = 0 \: \: \: \: \: \: or \: \: \: (x + 3 \sqrt{2} ) = 0 \\ = > x = \sqrt{2} and \: x = - 3 \sqrt{2}$

hope it helps ✔️