Question

solve the following quadratic equation by formula method p
6y
$6 {y}^{2} + 7y - 10 = 0 \\ by \: formula \: method$
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Answer 1

Given :-

$\sf \bullet \;\; 6y^{2} + 7y -10$

Solution :-

$\sf : \; \implies 6y^{2} + 7y -10 = 0$

$\sf : \; \implies 6y^{2} -5y + 12y-10 = 0$

$\sf : \; \implies y( 6y-5) + 2( 6y-5 ) = 0$

~Factor out common term 6y − 5 by using distributive property.

$\sf : \; \implies ( 6y-5)( y + 2) = 0$

$\sf : \; \implies 6y -5 = 0$

$\sf : \; \implies 6y = 0 + 5$

$\sf: \; \implies 6y = 5$

$\bf : \star \; \; y = \dfrac{5}{6}$

$\sf : \; \implies y + 2 = 0$

$\sf : \; \implies y = 0 -2$

$\bf : \star \; \; y = -2$

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Henceforth, the value of y can be 5/6 or -2