Solve the following quadratic equation by taking square roots. If 2(x−5)^2+4=22.
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The solutions to a quadratic equation of the form a{x}^{2}+bx+c=0 , a\ne 0 are given by the formula: ... Solve 2{x}^{2}+9x-5=0 ... We cannot take the square root of a negative number.
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Answer:
2(x−5)^2+4=22.
Step-by-step explanation:
hope it helps.
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