Solve the following quadratic equation by the completing the square 9x² + 24x + 16 = 0
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3
this is your answer. mark as brainlist
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ankurs25:
its not completing the sqare method........
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The pic has the wrong answer...
The correct answer is here:--
9x^2 + 24x + 16 = 0
=> x^2 + 24x/9 + 16/9 = 0
=> x^2 + 24x/9 = -16/9
=> (x)^2 + 2 × 24/18 × x + (24/18)^2 = (24/18)^2 -16/9
=> (x + 24/18 )^2 = 576/324 -16/9
=> (x + 24/18)^2= 576-576/324
=> (x + 24/18)^2 = 0
=> x + 24/18 = 0
=> x = -24/18
Therefore,
Required roots are as follows:-
x = -24/18 i.e -4/3
and x = -24/18 i.e. -4/3
Hope it helps !!
The pic has the wrong answer...
The correct answer is here:--
9x^2 + 24x + 16 = 0
=> x^2 + 24x/9 + 16/9 = 0
=> x^2 + 24x/9 = -16/9
=> (x)^2 + 2 × 24/18 × x + (24/18)^2 = (24/18)^2 -16/9
=> (x + 24/18 )^2 = 576/324 -16/9
=> (x + 24/18)^2= 576-576/324
=> (x + 24/18)^2 = 0
=> x + 24/18 = 0
=> x = -24/18
Therefore,
Required roots are as follows:-
x = -24/18 i.e -4/3
and x = -24/18 i.e. -4/3
Hope it helps !!
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hei bro b2- 4ac=0,so two real roots exist
and equal also
where am I wrong...thens ?
oooo...Hoo..sorry sorry plz post the question again
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