Solve the following quadratic equation by using formula-
x²-(1+√3)x +√3=0
Ans.=1, √3 in the textbook.
Please solve it quickly! I have to give it tomorrow as homework.
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Answered by
2
x^2 -(1+√3)x +√3 =0
x^2 - x -√3x +√3 =0
x (x - 1) - √3 (x -1)
(x-1) (x- √3)
x -1 =0
x = 1
or
x - √3 =0
x = √3
so , the answer is 1 , √3.
x^2 - x -√3x +√3 =0
x (x - 1) - √3 (x -1)
(x-1) (x- √3)
x -1 =0
x = 1
or
x - √3 =0
x = √3
so , the answer is 1 , √3.
Anonymous:
thanx for marking as brainliest
Solve the question by formula.
Which formula?
I solved it by factorization method
x=(-b+-D)/2a quadratic equation formula
Okk
Answered by
2
x²-(1+√3)x +√3=0
x²-x-√3x+√3=0
x(x-1) -√3(x-1)=0
(x-√3)(x-1)=0
either x=√3 or x=1
x²-x-√3x+√3=0
x(x-1) -√3(x-1)=0
(x-√3)(x-1)=0
either x=√3 or x=1
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