Math, asked by karanchaudhry, 1 year ago

solve the following quadratic equation for x :
4x^2-4a^2x+(a^4-b^4)=0

Answers

Answered by ihsaanwant
6

Answer:

x=(a^2+b^2)/2, x=(a^2-|b^2|)/2

Step-by-step explanation:

Maybe you've mistaken the question, it might be a typo error. The question most probably is 4x^2 - 4a^2x + (a4 – b4) = 0

Here you go with the answer:


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