Question

solve the following quadratic equation x^ + 100x - 300000

Answer 1

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$\color{green}bonjour$

$\color{blue}required \: answer$

x²+100x-30000

x²+600x-500x-300000

x(x+600)-500(x+600)

(x-500)(x+600)

$\color{indigo} \: now \: \: \: \: factor \: \: \: of \: \: \: this \: \: quardratic \: \\ \\ \\ \\ equation$

(x-500=0)

(x=500)

$\color{brown}again$

(x+600=0)

x=-600

$\color{yellow}{thanks}$

Answer 2

Hey !!!! ^_^

here is your answer

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x² + 100x - 300000

splitting 100x term


x² + 600x - 500x - 30000 = 0

x(x + 600) - 500(x + 600) = 0

(x + 600)(x - 500) = 0

x + 600 = 0 .....or .....x - 500 = 0

x = -600 .....or ..... x = 500



$i \: hope \: it \: will \: help \: you \\thnq$

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