Math, asked by reshmaqadiri, 4 months ago

Solve the following quadratic equation2y

2 + 27 y + 13 = 0

Answers

Answered by studyhard2005
1

Answer:

y =  \frac{ - 1}{2} \: \:   and \:  - 13

Step-by-step explanation:

2y² + 27y + 13 = 0

2y² + 26y + y + 13 = 0

2y (y + 13) + 1(y + 13) = 0

(2y + 1)(y + 13) = 0

y =  \frac{ - 1}{2} \: \:   and \:  - 13

Answered by DishaMaurya347
0

Answer:

y = -5/9

Step-by-step explanation:

2 + 27y + 13 = 0

15 + 27y = 0

27y = -15

y = -15/27

y = -5/9

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