Question

Solve the following quadratic equations: 14x² + 9x + 1 = 0 its urgent plazz reply


18

Answer 1

Step-by-step explanation:

Sum = 9 Prod = 14

14x² + 7x + 2x + 1 = 0

7x ( 2x +1 ) + 1 ( 2x + 1)

( 7x +1) ( 2x +1 )

Answer 2

Given :-

$14x {}^{2} + 9x + 1 = 0$

What to find out =Roots of the equation?

Solution :-

Factorise by splitting middle term

$14 {x}^{2} + 9x + 1 = 0 \\ \\ 14 {x}^{2} + 7x + 2x + 1 = 0 \\ \\ 7x(2x + 1) + 1(2x + 1) = 0 \\ \\ (2x + 1)(7x + 1) = 0$

Now split it into possible cases

$(2x + 1) = 0 \\ \\ (7x + 1) = 0$

Hence,

$x_1 = ( - \frac{1}{2} ) \\ \\ x_2 = ( - \frac{1}{7} )$

Extra information :-

• An equation containing a single variable of degree 2. Its general form is ax^2 + bx + c = 0, where x is the variable and a, b, and c are constants (a ≠ 0).