Question

SOLVE THE FOLLOWING QUADRATIC EQUATIONS BY COMPLETING THE SUQARE METHOD???​

Answer 1

Answer:

Hi ,

⭐ QUADRATIC EQUATIONS ⭐

(2). x²+ 2x - 5 = 0

x² + 2x = 5

x² + 2 × x × 1 + 1² = 5 + 1²

( x + 1 )² = 6

( x + 1 ) = ± √6

x = ±√6 - 1

x = √6 - 1 or x = -√6 - 1

(5). 2y² + 9y + 10 = 0

=> 2 ( y² + 9/2y + 5) = 0

=> y² + 9/2y + 5 = 0

=> y² + 9/2y = -5

=> y² + 9/2y + 81/¹6 = -5 + 81/4

=> (y + 9/4)² = 1/16

=> (y + 9/4) = ± 1/4

=> (y + 9/4) = 1/4 or (y + 9/4) = -1/4

=> y = -8/4 or y = -10/4

=> y = -2 or y = -5/2

I hope this helps you.

: )

Answer 2

Answer:

Now we can solve a Quadratic Equation in 3 steps:

Step 1 Divide all terms by a (the coefficient of x2).

Step 2 Move the number term (c/a) to the right side of the equation.

Step 3 Complete the square on the left side of the equation and balance this by adding the same value to the right side of the equation.