Question

Solve the following quadratic equations by factorization:√2x²-3x-2√2=0

Answer 1

Here is your answer hope it will help you .

Answer 2

The factors are (√2x + 1) and (x - 2√2).

Step-by-step explanation:

√2x² -3x -2√2 = 0

Factors of -4 are -4 and +1.

So √2x² -3x -2√2 = 0 can be written as:

√2x² -4x + x -2√2 = 0

√2x (x -2√2) + 1 (x -2√2) = 0

(√2x + 1) (x - 2√2) = 0

So the factors are (√2x + 1) and (x - 2√2).

x = 2√2 ,  -1/√2