Solve the following quadratic equations by factorization method.
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Answered by
6
3x² - 5x - 12 = 0
3x² - 9x + 4x - 12 = 0
3x(x - 3) + 4(x - 3) = 0
(3x + 4)(x - 3) = 0
x = 3 , x = -4/3
3x² - 9x + 4x - 12 = 0
3x(x - 3) + 4(x - 3) = 0
(3x + 4)(x - 3) = 0
x = 3 , x = -4/3
Answered by
12
Hola!
Given,
To factorise
3x² - 5x - 12 = 0
We know,
-12 × 3 = -36
And -9 × 4 = -36
So,
3x² - 9x + 4x - 12 = 0
=> 3x(x - 3) + 4(x - 3) = 0
=> (3x + 4)(x - 3) = 0
So,
3x + 4 = 0
=> x = -4/3
And
x - 3 = 0
=> x = 3
So,
x = -4/3 , 3
Peace out ✌️
Given,
To factorise
3x² - 5x - 12 = 0
We know,
-12 × 3 = -36
And -9 × 4 = -36
So,
3x² - 9x + 4x - 12 = 0
=> 3x(x - 3) + 4(x - 3) = 0
=> (3x + 4)(x - 3) = 0
So,
3x + 4 = 0
=> x = -4/3
And
x - 3 = 0
=> x = 3
So,
x = -4/3 , 3
Peace out ✌️
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