Question

Solve the following quadratic equations by factorization method.

Answer 1

3(x² - 6) = x(x + 7) - 3
3x² - 18 = x² + 7x - 3
3x² - x² - 18 + 3 - 7x = 0
2x² - 7x - 15 = 0
2x² - 10x + 3x - 15 = 0
2x(x - 5) + 3(x - 5) = 0
(2x + 3)(x - 5) = 0
x = 5 , x = -3/2

Answer 2

Hola!

Given,
To factorise

3(x² - 6) = x(x + 7) - 3
=>3x² - 18 = x² + 7x - 3
=>3x² - 18 - x² - 7x + 3 = 0
=>2x² - 7x - 15 = 0
=>2x² - 10x + 3x - 15 = 0
=>2x(x - 5) + 3(x - 5) = 0
=>(2x + 3)(x - 5) = 0

• 2x + 3 = 0
=> x = -3/2

And

• x - 5 = 0
=> x = 5

So,
x = -3/2 , 5


Peace out ✌️