Question

Solve the following quadratic equations by factorization method.

Answer 1

Hello user!!

Your answer follows :

$\sqrt{5}^{2}$ + 2x - 3√5

$\sqrt{5}^{2}$ + ( 5x - 3x ) - 3√5

( $\sqrt{5}^{2}$ + 5x ) - ( 3x - 3√5 )

√5x ( x - √5 ) - 3 ( x - √5 )

( √5x - 3 ) ( x - √5 )

√5x - 3 = 0

√5x = 0 + 3

x = $\frac{3}{\sqrt{5}}$

x - √5 = 0

x = 0 + √5

x = √5

values of x = $\boxed{3\div\sqrt{5}}$[/tex] & $\boxed{√5}$

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Answer 2

Given Quadratic equation ,

√5 x² + 2x - 3√5 = 0

Splitting the middle term ,

=> √5 x² +5x - 3x - 3√5 = 0

=>√5 x²+√5×√5x -3x-3√5=0

=> √5 x(x +√5) -3(x + √5) =0

=> ( x + √5 )( √5x - 3 ) = 0

=> x + √5 = 0 or √5 x - 3 = 0

x = -√5 or x = 3/√5

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