Question

Solve the following quadratic equations by factorization method.

Answer 1

Solution:-

given by:-
$x + \frac{1}{x} = \frac{26}{5} \\ \frac{ {x}^{2} + 1}{x} = \frac{26}{5} \\ 5 {x}^{2} - 26x + 5 = 0 \\ 5 {x}^{2} - 25x - x + 5 = 0 \\ 5x(x - 5) - 1(x - 5) = 0 \\ (x - 5)(5x - 1) = 0 \\ x = 5 \\ x = \frac{1}{5}$
☆i hope its help☆

Answer 2

HELLO DEAR,

${x + \frac{1}{x} = \frac{26}{5}}\\ \\ \frac{x^2 + 1}{x} = \frac{26}{5}\\ \\ 5x^2 + 5 = 26x\\ \\ 5x^2 - 26x + 5 = 0 \\ \\ 5x^2 - 25x - x + 5 = 0\\ \\ 5x(x - 5) - 1(x - 5) = 0\\ \\ (5x - 1)(x - 5)= 0 \\\\ x = \frac{1}{5} , x = 5$


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THANKS