Solve the following quadratic equations by factorization: abx²+b(²-ac)x-bc=0
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SOLUTION :
Given : abx² + b² - ac)x - bc = 0
abx² + b²x - acx - bc = 0
bx(ax + b) - c(ax + b) = 0
(bx - c) (ax + b) = 0
(bx - c) = 0 or (ax + b) = 0
[Equate each factor to zero]
bx = c or ax = - b
x = c/b or x = - b/a
Hence, the roots of the quadratic equation abx² + b² - ac)x - bc = 0 are c/b & - b/a .
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Answer:
abx² + b(²-ac)x - bc= 0
abx² + b²x - acx - bc= 0
bx(ax + b) - c(ax + b) = 0
(ax + b) (bx - c) = 0
ax + b = 0 or bx - c = 0
ax = - b or bx = c
x = - b/a or x = c/b
Step-by-step explanation:
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