Question

Solve the following quadratic equations by factorization: (x-3/x+3)-(x+3/x-3)=48/7,x≠3,x1≠3

Answer 1

done

hope it helps you...!

Answer 2

X = -4, +9/4

Step-by-step explanation:

(x-3)/(x+3) - (x+3)/(x-3) = 48/7

7* [(x-3)² - (x+3)²] = 48 (x+3)(x-3)

7 [x² + 9 -6x - (x² + 9 + 6x)] = 48 (x² - 9)

7(-12x) = 48x² - 432

48x² + 84x -432 = 0

Dividing by 12, we get:

4x² + 7x - 36 = 0

Factors of -144 are +16 and -9.

So  4x² + 7x - 36 = 0 can be written as:

 4x² + 16x -9x - 36 = 0

 4x (x +4) -9(x +4) = 0

(x + 4) (4x -9) = 0

So the factors are (x + 4) and (4x -9).

If x + 4 = 0, then x = -4

If 4x -9 = 0, then x = +9/4

Hence solved.

X = -4, +9/4