Solve the following quadratic equations for X: X square +(a/a+b +a+b/a) x+1 = 0
Answers
here's the solution
Given :
Quadratic equation in X
x² + [a/(a+b) + ( a+ b)/ a]x + 1 = 0
To Find :
Solution of given quadratic equation i.e. value of x
Solution :
• solution of quadratic equations is that value of x for which the given quadratic equation becomes zero or that value of x which satisfies the equation
•Solution of quadratic equation are also known as zeros of quadratic equation or roots of quadratic equation
•Given equation is
x² + [a/(a+b) + ( a+ b)/ a]x + 1 = 0
•It can be solved using Factorisation method
so, On multiplying x with
a/(a+b) + ( a+ b)/ a Equation becomes
x² + ax/(a+b) + ( a+ b)x/a + 1 = 0
•On taking x as common from first two terms & (a+b)/a as common from last two terms equation will become ,
x[x + a/(a+b)] + (a+b)/a[x + a/(a+b)] =0
•Now , it is clear that [x + a/(a+b)] is common in both terms
so, equation will become
[x + a/(a+b)].[x+ (a+b)/a] = 0
•Now , for equation to be zero
[x + a/(a+b)] = 0 or [x+ (a+b)/a] = 0
x = -a/(a+b) or x = -(a+b)/a
•Hence roots of given equation are
x = -a/(a+b) & x = -(a+b)/a