Question

Solve the following quadratic equations for X: X square +(a/a+b +a+b/a) x+1 = 0

Answer 1

hey mate

here's the solution

Answer 2

Given :

Quadratic equation in X

x² + [a/(a+b) + ( a+ b)/ a]x + 1 = 0

To Find :

Solution of given quadratic equation i.e. value of x

Solution :

• solution of quadratic equations is that value of x for which the given quadratic equation becomes zero or that value of x which satisfies the equation

•Solution of quadratic equation are also known as zeros of quadratic equation or roots of quadratic equation

•Given equation is

x² + [a/(a+b) + ( a+ b)/ a]x + 1 = 0

•It can be solved using Factorisation method

so, On multiplying x with

a/(a+b) + ( a+ b)/ a Equation becomes

x² + ax/(a+b) + ( a+ b)x/a + 1 = 0

•On taking x as common from first two terms & (a+b)/a as common from last two terms equation will become ,

x[x + a/(a+b)] + (a+b)/a[x + a/(a+b)] =0

•Now , it is clear that [x + a/(a+b)] is common in both terms

so, equation will become

[x + a/(a+b)].[x+ (a+b)/a] = 0

•Now , for equation to be zero

[x + a/(a+b)] = 0 or [x+ (a+b)/a] = 0

x = -a/(a+b) or x = -(a+b)/a

•Hence roots of given equation are

x = -a/(a+b) & x = -(a+b)/a