Math, asked by shreyash6276, 10 months ago

solve the following question

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Answered by sandy1816

3

Step-by-step explanation:

cosA+sinA=√2cosA

squaring both side

cos²A+sin²A+2sinAcosA=2cos²A

1+2sinAcosA=2(1-sin²A)

1+2sinAcosA=2-2sin²A

-1-2sinAcosA=-2+2sin²A

1-2sinAcosA=2sin²A

cos²A+sin²A-2sinAcosA=2sin²A

(CosA-sinA)²=2sin²A

cosA-SinA=√2sinA

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