Question

solve the following question​

Answer 1

Step-by-step explanation:

cosA+sinA=√2cosA

squaring both side

cos²A+sin²A+2sinAcosA=2cos²A

1+2sinAcosA=2(1-sin²A)

1+2sinAcosA=2-2sin²A

-1-2sinAcosA=-2+2sin²A

1-2sinAcosA=2sin²A

cos²A+sin²A-2sinAcosA=2sin²A

(CosA-sinA)²=2sin²A

cosA-SinA=√2sinA