Math, asked by bhaveshadekar04, 6 months ago

solve the following question​

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Answered by tyrbylent
0

Answer:

{0, 4}

Step-by-step explanation:

(x² - 5x + 12)(x + 4) = (x² - x - 4)(5x - 12)

x³ - 5x² + 12x + 4x² - 20x + 48 = 5x³ - 5x² - 20x - 12x² + 12x + 48

x³ - x² = 5x³ - 17x²

4x³ - 16x² = 0

4x²(x - 4) = 0

x_{1} = 0

x_{2} = 4

Answered by aayushsharma7956
0

Answer:

(0,4)

Step-by-step explanation:

(x+4)(x²-5x+12)=(5x-12)(x²-x-4)

x(x²-5x+12)+4(x²-5x+12)=5x(x²-x-4)-12(x²-x-4)

x³ - 5x² + 12x + 4x² - 20x + 48 = 5x³ - 5x² - 20x - 12x² + 12x + 48

x³ - x² = 5x³ - 17x²

4x³ - 16x² = 0

4x²(x - 4) = 0

x₁ = 0

x₂ = 4

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