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Hi !!
Perimeter of semicircular protector = 108
πR + 2R = 108
R ( π + 2 ) = 108
R ( 22/7 + 2 ) = 108
R ( 22 + 14 ) /7 = 108
R ( 36) = 108 × 7
R = ( 108 × 7 ) /36
R = 3 × 7
R = 21 cm
Perimeter of semicircular protector = 108
πR + 2R = 108
R ( π + 2 ) = 108
R ( 22/7 + 2 ) = 108
R ( 22 + 14 ) /7 = 108
R ( 36) = 108 × 7
R = ( 108 × 7 ) /36
R = 3 × 7
R = 21 cm
Answered by
0
Hence there is formula,
pi D/2 + D
We can also write D/2 = R and D = 2R
=> pi x R + 2R = 108 cm
Taking R as common,
=> R(pi + 2) = 108 cm
=> R (22/7 + 2) = 108 cm
=> R ( 22+14/7) = 108 cm
=> R x 36/7 = 108 cm
=> R = (108 x 7/36)
=> R = 756/36 cm
=> R = 21 cm
Be Brainly
pi D/2 + D
We can also write D/2 = R and D = 2R
=> pi x R + 2R = 108 cm
Taking R as common,
=> R(pi + 2) = 108 cm
=> R (22/7 + 2) = 108 cm
=> R ( 22+14/7) = 108 cm
=> R x 36/7 = 108 cm
=> R = (108 x 7/36)
=> R = 756/36 cm
=> R = 21 cm
Be Brainly
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