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as given in figure AD = DB SO d is mid point of line AB . similarly E also mid point of line AC.
and as we know that is two mid point of different lines of a triangle are added than that will be parallel to third line and half of that. therefore BC=2×DE.
and as we know that is two mid point of different lines of a triangle are added than that will be parallel to third line and half of that. therefore BC=2×DE.
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