solve the following question for x. using quadratic formula if possible 4x
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4x²= 3x
4x²-3x= 0 where a= 4, b= -3 and c= 0
quadratic formula---
x= [-b +or-✓(b²-4ac)] / 2a
Putting the values we get,
x= { -(-3) +or- ✓[(-3)² - (4*4*0)] } / 2*4
x= [ 3 +or- ✓(9-0) ] / 8
x= [3 + or - (3)] / 8
if x, = (3-3)/8 = 0/8. = 0
if x= (3+3)/8 = 6/8 = 3/4
So, x= 0 or 3/4
hope this helps you
4x²-3x= 0 where a= 4, b= -3 and c= 0
quadratic formula---
x= [-b +or-✓(b²-4ac)] / 2a
Putting the values we get,
x= { -(-3) +or- ✓[(-3)² - (4*4*0)] } / 2*4
x= [ 3 +or- ✓(9-0) ] / 8
x= [3 + or - (3)] / 8
if x, = (3-3)/8 = 0/8. = 0
if x= (3+3)/8 = 6/8 = 3/4
So, x= 0 or 3/4
hope this helps you
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