Solve the following questions -
1. For what value of a, x-3 is a factor of
x³+x²-17x+a?
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Answer:
x-3 is a factor of x³+x²-17x+a
x-3=0
x=3
P(x)=x³+x²-17x+a
P(3)=(3)³+(3)²-17×3+a
P(3)=27+8-51+a
P(3)=35-51+a
P(3)=-16+a
x-3 is a factor of x³+x²-17x+a
Therefore, remainder is 0
=>-16+a=0
=>a=16
Therefore the value of a is 16
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