solve the following questions
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1
given,
x+7 - 9
5 x-2
= (x+7)(x-2) -45
5(x-2)
= x²-2x+7x-14-45
5x-10
= x²+5x-59 -1
5x-10
⇒ x²+5x-59 = 5x -10
⇒x²-59+10 = 0
⇒x² -49 = 0
⇒(x+7)(x-7) = 0 since (a² -b²) = (a+b)(a-b)
⇒x = +7, -7
x+7 - 9
5 x-2
= (x+7)(x-2) -45
5(x-2)
= x²-2x+7x-14-45
5x-10
= x²+5x-59 -1
5x-10
⇒ x²+5x-59 = 5x -10
⇒x²-59+10 = 0
⇒x² -49 = 0
⇒(x+7)(x-7) = 0 since (a² -b²) = (a+b)(a-b)
⇒x = +7, -7
Anonymous:
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Answered by
1
- = 1
= 1
x² + 5x - 59 = 5x - 10
x² -49 = 0
x = 7 and -7
= 1
x² + 5x - 59 = 5x - 10
x² -49 = 0
x = 7 and -7
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