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If we let x and y be the two numbers, then the sum is x + y and the G.M. is 6√(xy). This givs:
x + y = 6√(xy)
==> (x + y)^2 = [6√(xy)]^2, from squaring
==> x^2 + 2xy + y^2 = 36xy
==> x^2 - 34xy + y^2 = 0.
By the Quadratic Formula:
(b^2 - 4ac = (-34y)^2 - 4(1)(y^2) = 1152y^2)
x = [-b +/- √(b^2 - 4ac)]/(2a)
= [34y +/- √(1152y^2)]/2
= (34y +/- 24y√2)/2
= (17 +/- 12√2)y.
However, since xy > 0, we require that the coefficient of y is positive. Thus:
x = (17 + 12√2)y.
This shows that:
x/y = 17 + 12√2 = (3 + 2√2)/(3 - 2√2), as required.
I hope this helps!
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