Solve the following recurrence relation by substitution
tn = tn-1 + n for n > 1
t1 = 1
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I don't know sorry but let this question pass to the expert ones
Answered by
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tn=tn-1+n
tn-tn=-1+n
0=n-1
n=1
there fore t1=tn
tn-tn=-1+n
0=n-1
n=1
there fore t1=tn
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