Math, asked by ratnadeepkaranjavkar, 4 months ago

solve the following simaltaneous equation . 4m+3n=18,3m-2n=5​

Answers

Answered by surenderkumar57
2

Answer:

4m+3n=18

4m=18-3n

m=18-3n/4. ( -2)

put the value of m in equation 2

3(18-3n/4)-2n=5

(54-9n/4)-2n=5

54-9n-8n

_______. =5

4

54-17n=20

-17n=20-54

-17n=-34

(-) 17n=34

n=34/17

n=2

put the value of n in equation 2

m=18-3(2)/4

m=18-6/4

m=12/4

m=3

Answered by verlasekhar
1

Answer:

from 1 equation

n=18-4m/3

=>3m-2(18-4m/3) =5

=>3m-36-8m/3=5

=>9m-8m-36/3=5

=>m-36=15

=>m=51

sub m=51 in 2 equation

3(51) -2n=5

=>153-2n=5

=>148=2n

=>n=74

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