solve the following simultaneous equation
1. x-y=2, 3x+2y-3z=13, x-3y-5z=3
2. x+2z=7, 2x-y+3z=9, y-z=1
3.3/x-4/y-6/z=-3, 2/y-6/x+3/z=1, 9/z-9/x+1/y=7/2
4.2/x+3/y+1/z=4, 4/x-6/y+3/z=-5, 3/x-5/y+2/z=-4
5.1/x=1/y=1, 1/y+1/z=2, 1/z+1/x=4
6.4/x+3/y=1, 9/y-8/z=5, 1/z+6/x=2
Answers
Answered by
35
Answer:
Step-by-step explanation:
3a+5b=26..(1)
a+5b=22..(2)
by elimination method
2*3, 3a+15b=66
(-) (-) (-⁻⁻⁻
-10b= -40
or, b = -40/ -10
or, b = 4
a+5b = 22
or, a+5*4= 22( putting b =4)
or, a+20 = 22
or, a = 22-20
or, a = 2
therefore, a = 2
b = 4
Answered by
36
Answer:
hope it helps you
refer to attachment
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