Math, asked by sruthipaapu2308, 14 days ago

solve the following simultaneous equation
1. x-y=2, 3x+2y-3z=13, x-3y-5z=3
2. x+2z=7, 2x-y+3z=9, y-z=1
3.3/x-4/y-6/z=-3, 2/y-6/x+3/z=1, 9/z-9/x+1/y=7/2
4.2/x+3/y+1/z=4, 4/x-6/y+3/z=-5, 3/x-5/y+2/z=-4
5.1/x=1/y=1, 1/y+1/z=2, 1/z+1/x=4
6.4/x+3/y=1, 9/y-8/z=5, 1/z+6/x=2

Answers

Answered by Anonymous
35

Answer:

Step-by-step explanation:

3a+5b=26..(1)

a+5b=22..(2)

by elimination method

2*3, 3a+15b=66

    (-)   (-)    (-⁻⁻⁻

           -10b= -40

       or, b = -40/ -10

       or, b = 4

a+5b = 22

or, a+5*4= 22( putting b =4)

or, a+20 = 22

or, a = 22-20

or, a = 2

therefore, a = 2

                b = 4            

               

Answered by pratyushara987
36

Answer:

hope it helps you

refer to attachment

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