Math, asked by saisawant, 4 months ago

Solve the following simultaneous equations. 1). 2x +3y +4=0; x-5y=11. ​

Answers

Answered by kamalagrawal48
1

Step-by-step explanation:

a. The given equation is 2x+3y−4=0

It can be written as 3y=−2x+4

  ⇒ \:  y = \frac{ - 2}{3} x +  \frac{4}{3}

which is in the required slope-intercept form.

On comparing with y=mx+c we get

m =  -  \frac{2}{3}  \: c =  \frac{4}{3}

hence \: slope \:  =  -  \frac{2}{3} \\ and \: y - intercept =  \frac{4}{3}

b. Simplifying

x + -5y = 11

Solving

x + -5y = 11

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '5y' to each side of the equation.

x + -5y + 5y = 11 + 5y

Combine like terms: -5y + 5y = 0

x + 0 = 11 + 5y

x = 11 + 5y

Simplifying

x = 11 + 5y

Hope its help you...

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