Question

solve the following simultaneous equations and find the value of x:150x+100y=10,260x+40y=10​

Answer 1

Answer:

• x = 0.48
• y = -0.62

Step-by-step explanation:

Given:

• Equations : 150 x + 100 y = 10 and 260 x + 40 y = 10

To Find:

• Value of x and y.

Formula/Method used:

• Substitution method.

Now, we will solve this equation by substitution method,

$\sf{\implies 150 x + 100 y = 10\;\;......(1)}$

$\sf{\implies 150x=10-100y}$

$\sf{\implies x=\dfrac{10-100y}{150}}$

Now, put the value of 'x' in 2nd equation,

$\sf{\implies 260x+40y=10\;\;......(2)}$

$\sf{\implies 260\Bigg[\dfrac{10-100y}{150}\Bigg]+40y=10}$

$\sf{\implies \dfrac{2600-26000y}{150}+40y=10}$

$\sf{\implies \dfrac{2600-26000y+6000y}{150}=100}$

$\sf{\implies 2600-20000y=15000}$

$\sf{\implies -20000y=15000-2600}$

$\sf{\implies -20000y=12400}$

$\sf{\implies y=-\dfrac{12400}{20000}}$

${\boxed{\boxed{\bf{\implies y=-0.62}}}}$

Now, put the value of 'y' in equation (1),

$\sf{\implies 150 x + 100 y = 10\;\;......(1)}$

$\sf{\implies 150x+100(-0.62)=10}$

$\sf{\implies 150x-62=10}$

$\sf{\implies 150x=72}$

$\sf{\implies x=\dfrac{72}{150}}$

${\boxed{\boxed{\bf{\implies x=0.48}}}}$

Answer 2

Answer:

answer is in pic

Step-by-step explanation:

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