solve the following simultaneous equations by the method of substitutions: 4x+2y=11,3x-5y=-8
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solve the following simultaneous equations by the method of substitutions: 4x+2y=11,3x-5y=-8
Answered by
1
From 1st equation,
x=(11-2y)/4
Put the value in 2nd equation,
[3(11-2y)/4]-5y=-8
33-6y-20y=-32 (multiplying by 3 then by 4)
33+32=20y+6y
65/26=y
y=5/2 i.e y=2.5
Now,put it in 1st equation
x=(11-2*2.5)/4
x=(11-5)/4
x=6/4
x=3/2 i.e x=1.5
Hence, x=1.5 and y=2.5
x=(11-2y)/4
Put the value in 2nd equation,
[3(11-2y)/4]-5y=-8
33-6y-20y=-32 (multiplying by 3 then by 4)
33+32=20y+6y
65/26=y
y=5/2 i.e y=2.5
Now,put it in 1st equation
x=(11-2*2.5)/4
x=(11-5)/4
x=6/4
x=3/2 i.e x=1.5
Hence, x=1.5 and y=2.5
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