A bike speeds up from a velocity of 6 m/s. It takes the bike 17 s to cover a distance of 262 m. What is the acceleration of the bike
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Answer:
s=ut+1/2at^2
262=6×17+1/2a(17)^2
262=102+289/2×a
160×2/289=a
a=1.1m/a
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