Question

Solve the following simultaneous equations using Cramer's rule:
y = 2x—19; 2x-3y + 3= 0​

Answer 1

Answer:

6.75 not sure but think so

Step-by-step explanation:

Solution

The given pair of linear equations are :

☆ 2x + y - 19 = 0 .....(i)

☆ 2x - 3y + 3 = 0 ......(ii)

By using elimination method ...

• By subtracting both the eq . , we get ,

2x + y - 19 = 0

2x - 3y + 3 = 0

(-) (-) (-)

_____________

-4y - 22 = 0

-4y = 22

y = 22÷ 4

y = 11/2

By putting the value of y in eq.(i) ....we get ...

2x + y - 19 = 0

= 2x + 11/2 - 19 = 0

= 2x + (11 - 38)÷2 = 0

= 2x - 27/2 = 0

= 2x = 27/2

= x = 27/4

= x = 6.75

Answer 2

Answer:

first write in a simple form

2x-y = 19 ;

2x-3y=-3

we have to find x & y

for x, Dx/D

for y, Dy/D

D = [ 2 -1 ] = 2(3) - (-2) = -4

[ 2 -3 ]

Dx = [19 -1] = -57-3 = -60

[-3 -3]

Dy = [2 19] = -6 -38 = -44

[2 -3]

for x, Dy/D = -60/-4

x = 15

for y, Dy/D = -44/-4

y = 11