Question

Solve the following simultaneous linear equation by substitution method 2x-3y/4=3. 5x-2y-7=0

Answer 1

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Answer 2

The given equations are: 2x - 3y/ 4 = 3 …..(i) 5x = 2y + 7 ……..(ii)

On multiplying (i) by 2 and (ii) by 3/4 , we get:

4x - 3/2 y = 6 …...

(iii) 15/4 x = 3/2 y + 21/ 4 ….(iv)

On subtracting (iii) and (iv), we get:

- 1/4 x = - 3/ 4

⇒x = 3

On substituting x = 3 in

(i), we get:

2 × 3 - 3y/4 = 3

⇒ 3y/4 =

(6 – 3) = 3

⇒y = (3 ×4 )/3 = 4

Hence, the solution is x = 3 and y = 4.